CS431 ASSIGNMENT 1 SOLUTION 2022

CS431 ASSIGNMENT 1 SOLUTION 2022

by

CS431 ASSIGNMENT 1 SOLUTION 2022. CS431 ASSIGNMENT 1 SOLUTION SPRING 2022

  • JOIN OUR SOCIAL MEDIA GROUPS
  • Join VU Best Telegram GroupVU ASSIGNMENTS, GDB, PAST PAPERS, QUIZZES, SOLUTIONSVU WHATSAPP GROUP LINKS
  • CS431 ASSIGNMENT 1 SOLUTION 2022. ASSIGNMENT no. 01
    Semester: spring 2022
    Wireless Communication – cs431 general marks: 15
    Due date: 17th can also 2021
    Question no.1 (five marks)
  • A wave of energy is transmitted fromthe source such as sender to receiver. It has an amplitude of 6.Eight cm, a time period of zero.01 seconds and the space from a crest to the neighboring trough of 14.8 cm. Via writing all necessary formulation and calculation steps, decide the frequency of this wave.
  • SEE ALSO:
  • MTH102 MIDTERM SOLVED PAPERS BY MOAAZ
  • Answer: as we realize that
    V = d/t = 0.148m/zero.01s = 14.8m/s
    Now
    V = f 
    So f = v/
    F = 14.8m/s
    6.8m = 2.18 hz
    Query no. 2 (five marks)
  • Calculate the wavelength of a wave, having speed/pace identical to 30,000 nm/s and frequency identical to 60 hertz.
    Answer: as we know that
  • V = 30,000nm/s = 30,000*10-9m/s = 0.3*10-4m/s
    V = f 
     = v/f
     = zero.3*10-4m/s
    60hz = zero.1/2*10-four = 5*10-7m
  • Observe: write all vital formulation, calculation steps along with the ideal unit with your answer.
  • Question no.Three (5 marks)
    Pick out one-way and -way verbal exchange examples from the following:
  • Instance one-way -manner
    Radio one-manner
    Cell phones -way
    Television one-way
    Wifi -manner
    Walkie talkie -way
    •
    Query no.1 (5 marks)
  • A wave of energy is transmitted fromthe source such as sender to receiver. It has an amplitude of 6.Eight cm, a term of 0.01 seconds and the gap from a crest to the neighboring trough of 14.Eight cm. By using writing all important formulation and calculation steps, decide the frequency of this wave.
  • Solution: as we know that
    V = d/t = 0.148m/0.01s = 14.8m/s
    Now
    V = f 
    So f = v/
    F = 14.8m/s
    6.8m = 2.18 hz
    Question no. 2 (5 marks)
    Calculate the wavelength of a wave, having velocity/speed identical to 30,000 nm/s and frequency identical to 60 hertz.
  • Solution: as we recognise that
    V = 30,000nm/s = 30,000*10-9m/s = zero.3*10-4m/s
    V = f 
     = v/f
     = 0.3*10-4m/s
    60hz = 0.0.5*10-four = five*10-7m
  • Be aware: write all essential formulation, calculation steps along side the appropriate unit with your answer.
  • Query no.3 (5 marks)
    Identify one-manner and -manner conversation examples from the following:
  • Instance one-way -manner
    Radio one-way
    Cell phones two-way
    Tv one-way
    Wifi -manner
    Walkie talkie two-manner
  • High-quality of success
  • CS431 ASSIGNMENT 1 SOLUTION 2021
  • CS431 ASSIGNMENT 1 SOLUTION SPRING 2021
  • GET SOLUTION FILE FROM HERE